Add a comment. Active Oldest Votes. Often when we are determining the answers to these types of questions, it is necessary to find the desired quantity as function of other variables. Then, it is sometimes the case that the desired quantity is actually independent of those variables.
I would up-vote you but I don't have enough reputation points yet. Do you understand the equation that I developed from the geometry of the situation? What step is giving you problems, this would help me to clear it up?
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Related 2. Hot Network Questions. Question feed. Mathematics Stack Exchange works best with JavaScript enabled. Draw a picture of the physical situation. See the figure. Write an equation that relates the quantities of interest.
Notice that the angles are identical in the two triangles, and hence they are similar. The ratio of their respective components are thus equal as well. Take the derivative with respect to time of both sides of your equation. Return to Related Rates Problems. Want access to all of our Calculus problems and solutions?
Shan, who is 2 meters tall, is approaching a post that holds a lamp 6 meters above the ground. You can read more about that sign-change in our reply to Kim in the comments below. Thanks for asking, Marissa! Hi there, when you find the relationship between L and x, why do you put the L-x and 1.
Is that like a rule or something that the smaller triangle components go on top? Thanks for asking, Nicky! But you could have written that instead as the inversion of both sides of that equation putting the larger values on top for BOTH sides , and the math would come out the same in the end.
In the above problem. Great question! The important thing is: does that set-up make sense to you? Please let us know! Got it. Hmm… I too did the same But getting a lengthy process Even though thanks for replying and giving me your time…. Thank you for your thanks, which we greatly appreciate.
That should give you all the values you need to substitute in and find your final answer. The solution given is the one where the person walks AWAY from the light.
I am trying to understand these problems, and this one confuses me. Unfortunately they can be annoyingly inconsistent about that, so you might have to try both the positive and negative values to see which it accepts. Log in. Home » Calculus 1 » Related Rates. Calculus Related Rates Problem: Lamp post casts a shadow of a man walking.
Calculus Solution [Scroll down for text non-video version of the solution.
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